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6.1.2. Definition.
Let F be an extension field of K and let
u
F.
If there exists a nonzero polynomial
f(x)
K[x]
such that f(u)=0, then u is said to be
algebraic
over K.
If there does not exist such a polynomial, then u is said to be
transcendental
over K.
6.1.3. Proposition.
Let F be an extension field of K, and let
u
F be algebraic over K.
Then there exists a unique monic irreducible polynomial
p(x)
K[x]
such that p(u)=0.
It is characterized as the monic polynomial of minimal degree
that has u as a root.
Furthermore, if f(x) is any polynomial in K[x] with f(u)=0, then p(x) | f(x).
6.1.4. Definition. Let F be an extension field of K, and let u be an algebraic element of F. The monic polynomial p(x) of minimal degree in K[x] such that p(u)=0 is called the minimal polynomial of u over K. The degree of the minimal polynomial of u over K is called the degree of u over K.
6.1.5. Definition.
Let F be an extension field of K, and let
u1,
u2,
. . . ,
un
F.
The smallest subfield of F that contains K and
u1,
u2,
. . . ,
un
will be denoted by
K ( u1, u2, . . . , un ).
It is called the extension field of K generated by u1, u2, . . . , un .
F,
then F is said to be a
simple extension of K.
6.1.6. Proposition.
Let F be an extension field of K, and let
u
F.
K[x]/<p(x)>,
where p(x) is the minimal polynomial of u over K.
K(x),
where K(x) is the quotient field of the integral domain K[x].
6.1.7. Proposition.
Let K be a field and let
p(x)
K[x]
be any irreducible polynomial.
Then there exists an extension field F of K and an element
u
F
such that the minimal polynomial of u over K is p(x).
F
be an element algebraic over K.
If the minimal polynomial of u over K has degree n,
then K(u) is an n-dimensional vector space over K.
6.2.2. Definition.
Let F be an extension field of K.
If the dimension of F as a vector space over K is finite,
then F is said to be a
finite
extension of K.
The dimension of F as a vector space over K is called the
degree
of F over K, and is denoted by [F:K].
6.2.3. Proposition.
Let F be an extension field of K and let
u
F.
The following conditions are equivalent:
[F:K] = [F:E][E:K].
6.2.5. Corollary. Let F be a finite extension of K. Then the degree of any element of F is a divisor of [F:K].
6.2.6 Corollary.
Let F be an extension field of K, with algebraic elements
u1,
u2,
. . . ,
un
F.
Then the degree of
K ( u1, u2, . . . , un )
over K is at most the product of the degrees of ui over K, for 1
i
n.
6.2.7. Corollary. Let F be an extension field of K. The set of all elements of F that are algebraic over K forms a subfield of F.
6.2.8. Definition. An extension field F of K is said to be algebraic over K if each element of F is algebraic over K.
6.2.9. Proposition. Every finite extension is an algebraic extension.
Example. 6.2.3. (Algebraic numbers)
Let Q* be the set of all complex numbers
u
C
such that u is algebraic over Q.
Then Q* is a subfield
of C by Corollary 6.2.7, called the
field of algebraic numbers.
6.2.10. Proposition. Let F be an algebraic extension of E and let E be an algebraic extension of K. Then F is an algebraic extension of K.
6.3.2. Proposition. The set of all constructible real numbers is a subfield of the field of all real numbers.
6.3.3. Definition.
Let F be a subfield of R.
The set of all points (x,y) in the Euclidean plane
R2
such that x,y
F is called the
plane
of F.
A straight line with an equation of the form
ax+by+c = 0, for elements a,b,c
F,
is called a
line in F.
Any circle with an equation of the form
x2 + y2 + ax + by + c = 0, for
elements a,b,c
F,
is called a
circle in F.
6.3.4. Lemma. Let F be a subfield of R.
u),
for some u
F.
6.3.6. Theorem. The real number u is constructible if and only if there exists a finite set u1, u2, . . . , un of real numbers such that
Q,
Q(u1,...,ui-1),
for i=2,..., and
Q(u1,...,un).
6.3.9. Theorem. It is impossible to find a general construction for trisecting an angle, duplicating a cube, or squaring a circle.
F
such that
6.4.2. Theorem.
Let
f(x)
K[x] be a polynomial of degree
n>0.
Then there exists a splitting field F for f(x) over K, with
[F:K]
n!.
6.4.3. Lemma.
Let
: K -> L be an isomorphism of fields.
Let F be an extension field of K such
that F = K(u) for an algebraic element
u
F.
Let p(x) be the minimal polynomial of u over K.
If v is any root of the image q(x) of p(x) under
,
and E=L(v), then there is a unique way to extend
to an isomorphism
: F -> E such that
(u) = v and
(a) =
(a)
for all a
K.
6.4.5. Theorem. Let f(x) be a polynomial over the field K. The splitting field of f(x) over K is unique up to isomorphism.
If F is any field, then the smallest subfield of F that contains the identity element 1 is called the prime subfield of F. If F is a finite field, then its prime subfield is isomorphic to Zp, where p=chr(F) for some prime p.
6.5.2. Theorem. Let F be a finite field with k = pn elements. Then F is the splitting field of the polynomial xk-x over the prime subfield of F.
Example 6.5.1. [Wilson's theorem] Let p > 2 be a prime number. Then
(p-1)!
-1 (mod p).
6.5.4. Lemma.
Let F be a field of prime characteristic p, let
n
Z+,
and let k = pn. Then
{ a
F | ak = a }
6.5.5. Proposition. Let F be a field with pn elements. Each subfield of F has pm elements for some divisor m of n. Conversely, for each positive divisor m of n there exists a unique subfield of F with pm elements.
6.5.6. Lemma. Let F be a field of characteristic p. If n is a positive integer not divisible by p, then the polynomial xn-1 has no repeated roots in any extension field of F.
6.5.7. Theorem. For each prime p and each positive integer n, there exists a field with pn elements.
6.5.8. Definition.
Let p be a prime number and let
n
Z+.
The field (unique up to isomorphism) with
pn
elements is called the
Galois field of order pn,
denoted by GF(pn).
6.5.9. Lemma.
Let G be a finite abelian group. If
a
G is an element of maximal order in G,
then the order of every element of G is a divisor of the order of a.
6.5.10. Theorem. The multiplicative group of nonzero elements of a finite field is cyclic.
6.5.11. Theorem. Any finite field is a simple extension of its prime subfield.
6.5.12. Corollary. For each positive integer n there exists an irreducible polynomial of degree n over GF(p).
Convention:
In the notation
d | n
and
d | n
we will assume that d | n refers to the positive divisors of n.
6.6.2. Definition.
If d is a positive integer, we define the
Moebius
function
(d) as follows:
(1) = 1;
(d) = 1
if d has an even number of prime factors (each occurring only once);
(d) = -1
if d has an odd number of prime factors (each occurring only once);
(d) = 0
if d is divisible by the square of a prime.
Z+
and gcd(m,n)=1, then
(mn) =
(m)
(n).
f(mn) = f(m)f(n),
whenever gcd(m,n)=1.6.6.4. Proposition. Let R be a commutative ring, and let f : Z+ -> R be a multiplicative function. If F : Z+ -> R is defined by
F(n) =
d | n
f(d),
Z+, then F is a multiplicative function.
6.6.5. Proposition. For any positive integer n,
d | n
(d) = 1 if n = 1, and
d | n
(d) = 0 if n > 1.
F(n) =
d | n
f(d),
for all
n
Z+,
f(m)
=
n | m
( m/n ) F(n),
for all
m
Z+.
G(n) =
d | n
g(d), for all
n
Z+,
g(m) =
n | m
G(n)k,
for all
m
Z+,
( m/n ).
6.6.8. Definition. The number of irreducible polynomials of degree m over the finite field GF(q), where q is a prime power, will be denoted by Iq(m).
The following formula for Iq(m) is due to Gauss.
6.6.9. Theorem. For any prime power q and any positive integer m,
Iq(m) = (1/m)
d | m
( m / d ) qd.
1.
a.
Then a is called a
quadratic residue modulo n
if the congruence
x2
a(mod n)
is solvable, and a
quadratic nonresidue
otherwise.
=1
if a is a quadratic residue modulo n and
=-1
if a is a quadratic nonresidue modulo n. The symbol
is called the
Legendre symbol.
6.7.2. Proposition. [Euler's Criterion]
If p is an odd prime, and if
a
Z with
p
a, then
, and
, where k = (p2 - 1)/8.