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Theorem 6.6.1.
Let F = GF(q), where q = pn, and let k = qm.
The irreducible factors of xk - x
in F[x] are precisely the monic irreducible polynomials in F[x]
whose degree is a divisor of m.
Convention:
In the notation
d | n
and
d | n
we will assume that d | n refers to the positive divisors of n.
Definition 6.6.2.
If d is a positive integer, we define the
Moebius
function
(d) as follows:
(1) = 1;
(d) = 1
if d has an even number of prime factors (each occurring only once);
(d) = -1
if d has an odd number of prime factors (each occurring only once);
(d) = 0
if d is divisible by the square of a prime.
Proposition 6.6.3.
If m, n are positive integers with gcd(m,n)=1, then
(mn) =
(m)
(n).
If R is a commutative ring, then a function
f : Z+ -> R
is said to be a
multiplicative
function if
f(mn) = f(m)f(n),
whenever gcd(m,n)=1.
Proposition 6.6.4.
Let R be a commutative ring, and let
f : Z+ -> R
be a multiplicative function. If
F : Z+ -> R
is defined by
F(n) =
d | n
f(d),
Proposition 6.6.5.
For any positive integer n,
d | n
(d) = 1 if n = 1, and
d | n
(d) = 0 if n > 1.
Theorem 6.6.6. [Moebius Inversion Formula]
Let R be a commutative ring, and let
f : Z+ -> R
be any function. If the function
F : Z+ -> R
is defined by
F(n) =
d | n
f(d),
f(m)
=
n | m
( m/n ) F(n),
Theorem 6.6.7. [Moebius Inversion Formula (2)]
Let R be a commutative ring, and let
g : Z+ -> R
be any function. If the function
G : Z+ -> R
is defined by
G(n) =
d | n
g(d),
g(m) =
n | m
G(n)k,
( m/n ).
Definition 6.6.8.
The number of irreducible polynomials of degree m
over the finite field GF(q), where q is a prime power,
will be denoted by Iq(m).
The following formula for Iq(m) is due to Gauss.
Theorem 6.6.9.
For any prime power q and any positive integer m,
Iq(m) = 1/m
d | m
( m / d ) qd.
Corollary 6.6.10.
For all positive integers m and all prime powers q we have
Iq(m)
1.
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