Solution: Let H be a subgroup of an abelian group G. If x belongs to H and g belongs to G, then gxg-1 = gg-1x = x belongs to H.
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2.
Let G1 and G2 be groups,
and let G be the direct product G1 × G2.
Let H = { (x1,x2) in G1 × G2
| x2 = e } and
K = { (x1,x2) in G1 × G2
| x1 = e }.
Prove that H and K are normal subgroups of G.
Note: Exercise 3.3.9 in the text
shows that H and K are subgroups
for which HK = G and
H
K = {e}.
Solution: If (x1,e) is any element of H, and (g1,g2) is any element of G1 × G2, then
(g1,g2)
(x1,e)
(g1,g2) -1
=
(g1,g2)
(x1,e)
(g1 -1,g2 -1)
=
(g1x1g1 -1,
g2 e g2 -1)
=
(g1x1g1 -1,e).
Since (g1x1g1 -1,e) belongs to H, this shows that H is a normal subgroup of G. A similar argument shows that K is also a normal subgroup of G.
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