Exercise 4 (page 71 in Stewart)
The point P(0.5,2) lies on the curve y = 1/x.
If Q is the point (x,1/x), use your calculator
to find the slope of the secant line PQ
for the following values of x:
(i) 2 (ii) 1 (iii) 0.9
key to call the function editor,
and enter the function y1 = 1/x.
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| Y1=1/x |
| Y2= |
| Y3= |
| Y4= |
| Y5= |
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.
to enter a " : ".
key to do the calculation.
Your screen should look like this:
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| 2->X:(Y1-2)/(X-.5) |
| -1 |
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to recall your previous entry.
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| 2->X:(Y1-2)/(X-.5) |
| -1 |
| 1->X:(Y1-2)/(X-.5) |
| -2 |
| .9->X:(Y1-2)/(X-.5) |
| -2.22222222222 |
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Note: Here is the general form of the slopes you are evaluating.